C-03-Q181mediumsingle_mcqSame setup. Speed of current = ?ad2(1q−1p)\dfrac{d}{2}\left(\dfrac{1}{q} - \dfrac{1}{p}\right)2d(q1−p1)bd2(1p−1q)\dfrac{d}{2}\left(\dfrac{1}{p} - \dfrac{1}{q}\right)2d(p1cd2(1p+1q)\dfrac{d}{2}\left(\dfrac{1}{p} + \dfrac{1}{q}\right)2d(p1dd(q−p)d(q - p)d(q−p)