C-03-Q171mediumsingle_mcqSame setup. Speed of current = ?ax2(1t2−1t1)\dfrac{x}{2}\left(\dfrac{1}{t_2} - \dfrac{1}{t_1}\right)2x(t21−t11bx2(1t1+1t2)\dfrac{x}{2}\left(\dfrac{1}{t_1} + \dfrac{1}{t_2}\right)2x(tcx2(1t1−1t2)\dfrac{x}{2}\left(\dfrac{1}{t_1} - \dfrac{1}{t_2}\right)2x(tdx(t1−t2)x(t_1 - t_2)x(t1−t2)