C-03-Q058: If $a+b+c=6$ and $a^2+b^2+c^2=14$, $(a-b)^2+(b-c)^2+(c-a)^2 = ?$

C-03-Q058: If $a+b+c=6$ and $a^2+b^2+c^2=14$, $(a-b)^2+(b-c)^2+(c-a)^2 = ?$ | প্রশ্ন করি

If a+b+c=6a+b+c=6a+b+c=6 and a2+b2+c2=14a^2+b^2+c^2=14a2+b2+c2=14, (a−b)2+(b−c)2+(c−a)2=?(a-b)^2+(b-c)^2+(c-a)^2 = ?(a−b)2+(b−c)2+