C-08-Q171mediumsingle_mcqIn 0<θ<π20 < \theta < \dfrac{\pi}{2}0<θ<2π, the equation 2sin2θ+3cosθ=32\sin^{2}\theta + 3\cos\theta = 32sin2θ+3cosθ=3 gives cosθ\cos\thetacosθ equal to —a12\dfrac{1}{2}21b12\dfrac{1}{\sqrt{2}}