C-08-Q160mediumsingle_mcqIn 0<θ<π20 < \theta < \dfrac{\pi}{2}0<θ<2π, the solution of sinθ+cosθ=2\sin\theta + \cos\theta = \sqrt{2}sinθ+cosθ=2 is —aπ6\dfrac{\pi}{6}6πbπ4\dfrac{\pi}{4}4