If $\cos A = \dfrac{4}{5}$ and $\sin B = \dfrac{12}{13}$ ($A,B$ acute), the value of $\dfrac{ an B - an A}{1 + an B

Question

If $\cos A = \dfrac{4}{5}$ and $\sin B = \dfrac{12}{13}$ ($A,B$ acute), the value of $\dfrac{	an B - 	an A}{1 + 	an B	an A}$ is —

Accepted Answer

$\dfrac{33}{56}$

Answer

$\dfrac{56}{33}$

Answer

$\dfrac{33}{65}$

Answer

$\dfrac{16}{65}$

If cos⁡A=45\cos A = \dfrac{4}{5}cosA=54​ and sin⁡B=1213\sin B = \dfrac{12}{13}sinB=1312​ (A,BA,BA,B acute), the value of tan⁡B−tan⁡A1+tan⁡Btan⁡A\dfrac{\tan B - \tan A}{1 + \tan B\tan A}1+tanBtanAtanB−tanA​ is —