C-08-Q070mediumsingle_mcqcotθ\cot\thetacotθ equals —aperpendicularbase\dfrac{\text{perpendicular}}{\text{base}}baseperpendicularbbaseperpendicular\dfrac{\text{base}}{\text{perpendicular}}perpendicularbasechypotenusebase\dfrac{\text{hypotenuse}}{\text{base}}basehypotenusedbasehypotenuse\dfrac{\text{base}}{\text{hypotenuse}}hypotenusebase