C-08-Q067mediumsingle_mcqtanθ\tan\thetatanθ equals —aperpendicularhypotenuse\dfrac{\text{perpendicular}}{\text{hypotenuse}}hypotenuseperpendicularbbaseperpendicular\dfrac{\text{base}}{\text{perpendicular}}perpendicularbasecperpendicularbase\dfrac{\text{perpendicular}}{\text{base}}baseperpendiculardhypotenusebase\dfrac{\text{hypotenuse}}{\text{base}}basehypotenuse