For two tossings of an unbiased coin, the probability of getting exactly one head, $P(1H)$, is —

Question

Accepted Answer

$\frac{1}{2}$

Answer

$\frac{1}{4}$

Answer

$\frac{3}{4}$

Answer

$\frac{1}{8}$

For two tossings of an unbiased coin, the probability of getting exactly one head, P(1H)P(1H)P(1H), is —