In an isosceles $ riangle ABC$ with $AB = AC$, $AD$ is the perpendicular from $A$ to base $BC$. If $R$ is the circumrad

Question

In an isosceles $	riangle ABC$ with $AB = AC$, $AD$ is the perpendicular from $A$ to base $BC$. If $R$ is the circumradius of the triangle, then $AB^2 =$

Accepted Answer

$2 R \cdot AD$

Answer

$R \cdot AD$

Answer

$R^2 + AD^2$

Answer

$\dfrac{R \cdot AD}{2}$

In an isosceles △ABC\triangle ABC△ABC with AB=ACAB = ACAB=AC, ADADAD is the perpendicular from AAA to base BCBCBC. If RRR is the circumradius of the triangle, then AB2=AB^2 =AB2=

In an isosceles $\triangle ABC$ with $AB = AC$ , $AD$ is the perpendicular from $A$ to base $BC$ . If $R$ is the circumradius of the triangle, then $AB^2 =$