In $ riangle ABC$, the perpendiculars $AD, BE, CF$ from the vertices to the opposite sides intersect at $O$. Then —

Question

In $	riangle ABC$, the perpendiculars $AD, BE, CF$ from the vertices to the opposite sides intersect at $O$. Then —

Accepted Answer

$AO \cdot OD = BO \cdot OE = CO \cdot OF$

Answer

$AO + OD = BO + OE = CO + OF$

Answer

$\dfrac{AO}{OD} = \dfrac{BO}{OE} = \dfrac{CO}{OF}$

Answer

$AO = OD$, $BO = OE$, $CO = OF$

In △ABC\triangle ABC△ABC, the perpendiculars AD,BE,CFAD, BE, CFAD,BE,CF from the vertices to the opposite sides intersect at OOO. Then —