In a cyclic quadrilateral $ABCD$ with perpendicular diagonals $AC$ and $BD$ meeting at $M$, $ME \perp BC$ and the extend

Question

In a cyclic quadrilateral $ABCD$ with perpendicular diagonals $AC$ and $BD$ meeting at $M$, $ME \perp BC$ and the extended $EM$ meets $AD$ at $F$. Then —

Accepted Answer

$AF = FD$

Answer

$AF = 2 FD$

Answer

$AF + FD = AC$

Answer

$AF \cdot FD = AB^2$

In a cyclic quadrilateral ABCDABCDABCD with perpendicular diagonals ACACAC and BDBDBD meeting at MMM, ME⊥BCME \perp BCME⊥BC and the extended EMEMEM meets ADADAD at FFF. Then —

In a cyclic quadrilateral $ABCD$ with perpendicular diagonals $AC$ and $BD$ meeting at $M$ , $ME \perp BC$ and the extended $EM$ meets $AD$ at $F$ . Then —