C-03-Q036mediumsingle_mcq

In $\triangle ABC$ , $\angle B = 120°$ . Then $AC^2 =$

A B^{2} + B C^{2} - A B \cdot B C

c

AB^2 + BC^2 + AB \cdot BC

d

AB^2 - BC^2

In △ABC\triangle ABC△ABC, ∠B=120°\angle B = 120°∠B=120°. Then AC2=AC^2 =AC2=