If $a^2 + b^2 = 7ab$, then $\log\!\left(\dfrac{a+b}{3}\right)$ equals:

Question

Accepted Answer

$\dfrac{1}{2}(\log a + \log b)$

Answer

$\log a + \log b$

Answer

$\log(ab)$

Answer

$2 \log(ab)$

If a2+b2=7aba^2 + b^2 = 7aba2+b2=7ab, then log⁡ ⁣(a+b3)\log\!\left(\dfrac{a+b}{3}\right)log(3a+b​) equals: