The base-change formula states $\log_a M$ equals:

Question

Accepted Answer

both a and c

Answer

$\log_b M \cdot \log_a b$

Answer

$\log_b M + \log_a b$

Answer

$\dfrac{\log_b M}{\log_b a}$ as well

The base-change formula states log⁡aM\log_a Mloga​M equals: