C-09-Q062mediumsingle_mcqIf a=2+21/3+22/3a = 2 + 2^{1/3} + 2^{2/3}a=2+21/3+22/3, then a3−6a2+6a−2a^3 - 6a^2 + 6a - 2a3−6a2+6a−2 equals:a000b111c−1-1−1d