If $f(x) = x^2 - 6x + 15,\ g(x) = x^2 - 6x + 13$ and $\sqrt{f(x)} - \sqrt{g(x)} = \sqrt{10} - \sqrt{8}$, then $x$ equals

Question

If $f(x) = x^2 - 6x + 15,\ g(x) = x^2 - 6x + 13$ and $\sqrt{f(x)} - \sqrt{g(x)} = \sqrt{10} - \sqrt{8}$, then $x$ equals —

Accepted Answer

$1,\ 5$

Answer

$2,\ 3$

Answer

$-1,\ 5$

Answer

$1,\ -5$

If f(x)=x2−6x+15, g(x)=x2−6x+13f(x) = x^2 - 6x + 15,\ g(x) = x^2 - 6x + 13f(x)=x2−6x+15, g(x)=x2−6x+13 and f(x)−g(x)=10−8\sqrt{f(x)} - \sqrt{g(x)} = \sqrt{10} - \sqrt{8}f(x)​−g(x), then xxx equals —