The solutions of $8 \cdot 27^x = 4^y,\ 9^x \cdot 3^{xy} = \dfrac{1}{3}$ are —

Question

Accepted Answer

$(-1, 1)$ and $(3, -3)$

Answer

$(1, -1)$ and $(-3, 3)$

Answer

$(0, 0)$ only

Answer

$(2, 1)$ and $(1, 2)$

The solutions of 8⋅27x=4y, 9x⋅3xy=138 \cdot 27^x = 4^y,\ 9^x \cdot 3^{xy} = \dfrac{1}{3}8⋅27x=4y, 9x⋅3xy=31​ are —