C-05-Q057mediumsingle_mcqThe solution of 32x−2−5⋅3x−2−66=03^{2x-2} - 5 \cdot 3^{x-2} - 66 = 032x−2−5⋅3x−2−66=0 is —ax=3x = 3x=3bx=−3x = -3x=−3cx=2x = 2