C-05-Q053mediumsingle_mcqThe solution of 22x−3⋅ax−2=2x−3⋅4a1−x (a>0, a≠1/2)2^{2x-3} \cdot a^{x-2} = 2^{x-3} \cdot 4a^{1-x}\ (a > 0,\ a \neq 1/2)22x−3⋅ax−2=2x−3⋅4a1−x (a>0, a=1/2) is —ax=3/2x = 3/2x=3/2bx=5/2x = 5/2x=5/2cx=−