To solve $\sqrt{x^2 - 6x + 9} - \sqrt{x^2 - 6x + 6} = 1$, replacing $x^2 - 6x + 6 = y$ gives —

Question

Accepted Answer

$\sqrt{y+3} - \sqrt{y} = 1$

Answer

$\sqrt{y} - \sqrt{y+3} = 1$

Answer

$\sqrt{y} + \sqrt{y+3} = 1$

Answer

$y + 3 = 1$

To solve x2−6x+9−x2−6x+6=1\sqrt{x^2 - 6x + 9} - \sqrt{x^2 - 6x + 6} = 1x2−6x+9​−x2−6x+6​=1, replacing x2−6x+6=yx^2 - 6x + 6 = yx2−6x+6=y gives —