The area of a triangle with vertices $(x_1,y_1)$, $(x_2,y_2)$, $(x_3,y_3)$ in anti-clockwise order is —

Question

Accepted Answer

$\frac{1}{2}|x_1y_2+x_2y_3+x_3y_1-x_2y_1-x_3y_2-x_1y_3|$

Answer

$|x_1y_2+x_2y_3+x_3y_1|$

Answer

$\sqrt{x_1y_2+x_2y_3+x_3y_1}$

Answer

$x_1+x_2+x_3$

The area of a triangle with vertices (x1,y1)(x_1,y_1)(x1​,y1​), (x2,y2)(x_2,y_2)(x2​,y2​), (x3,y3)(x_3,y_3)(x3​,y3​) in anti-clockwise order is —