Suppose $P(x) = ax^5 + bx^4 + cx^3 + cx^2 + bx + a$ where $a
eq 0$. If $(x - r)$ is a factor of $P(x)$, then another f

Question

Suppose $P(x) = ax^5 + bx^4 + cx^3 + cx^2 + bx + a$ where $a 
eq 0$. If $(x - r)$ is a factor of $P(x)$, then another factor of $P(x)$ is:

Accepted Answer

$(rx - 1)$

Answer

$(rx + 1)$

Answer

$(x - r^2)$

Answer

$(x + r)$

Suppose P(x)=ax5+bx4+cx3+cx2+bx+aP(x) = ax^5 + bx^4 + cx^3 + cx^2 + bx + aP(x)=ax5+bx4+cx3+cx2+bx+a where a≠0a \neq 0a=0. If (x−r)(x - r)(x−r) is a factor of P(x)P(x)P(x), then another factor of P(x)P(x)P(x) is: