C-08-Q163mediumsingle_mcqThe reaction at the cathode of NaCl solution electrolysis:aHX++eX−→H\ce{H+ + e- -> H}HX++eX− then H+H→HX2\ce{H + H -> H2}H+HHXbNaX++eX−→Na\ce{Na+ + e- -> Na}NaX++eXcClX−→Cl+eX−\ce{Cl- -> Cl + e-}ClX−dOX2+4 eX−→2 OX2−\ce{O2 + 4e- -> 2O^2-}OX2+4