$\mathrm{FeSO_4 + 2NaOH o Fe(OH)_2{\downarrow} + Na_2SO_4}$ — the colour of the precipitate is—

Question

$\mathrm{FeSO_4 + 2NaOH 	o Fe(OH)_2{\downarrow} + Na_2SO_4}$ — the colour of the precipitate is—

Accepted Answer

green

Answer

white

Answer

blue

Answer

red

FeSO4+2NaOH→Fe(OH)2↓+Na2SO4\mathrm{FeSO_4 + 2NaOH \to Fe(OH)_2{\downarrow} + Na_2SO_4}FeSO4​+2NaOH→Fe(OH)2​↓+Na2​SO — the colour of the precipitate is—